Dear Student , As you have not said us which question is to be solved so we are unable to solve this Kindly ask a question properly so that we can help you to solve this Though we are solbving one of the question 2 4 Sun's angular diameter =α=1920"=1920×4 85×10-8 rad=9 31×10-5 radSun's diameter =d=αD=9 31×10-5×1 496×1011=1 39×107 m Your question is not clear and appears to be incomplete Recheck your question and please be a little specific so that we can provide you with some meaningful help Looking forward to hear from you again! Regards

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Solve this: mg. 2.2 Having determined D. similar to determine the size or of the If d is the nfthe plan u size of the lthe hy the earth), The angle he earth It is e angle AO; 01 sight Fig. = 401 mm Fig. 2.3. AR = Acta te 2 3 The moon w e qu i c kly on The 8 subtended th t •o directions "hen two 01 the the Si 01 be Eq. (2 21 red, we 21 rad rad 1 100 the DO is - 2rad. D=b/8 =3.84x1cVm Remple2_4 sum L4c•L; x 10 r Sun s a - 1920" -9.31x10"rad of thi equal solution 20 Next w it 20 e neentratiml of the e lightly sprinkle 2.3.2 1.39x10am Estimtion of Size of a powder surlåce of water a I mugh put drop of this in The oleic acid drop sweads into a rmvghly 01 the 01' the thin Lo get its we have dmp1Rd n dmps Initially.

Dear Student ,
As you have not said us which question is to be solved so we are unable to solve this .Kindly ask a question properly so that we can help you to solve this .Though we are solbving one of the question .
2.4.

S u n' s a n g u l a r d i a m e t e r = α = 1920 " = 1920 \times 4.85 \times 10^{- 8} r a d = 9.31 \times 10^{- 5} r a d S u n' s d i a m e t e r = d = α D = 9.31 \times 10^{- 5} \times 1.496 \times 10^{11} = 1.39 \times 10^{7} m

Your question is not clear and appears to be incomplete. Recheck your question and please be a little specific so that we can provide you with some meaningful help. Looking forward to hear from you again!
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