# Solve this:

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Please find below the solution of example 21:

For calculating the equivalent mass of these compounds we use the following relation-

Equivalent mass =     (as we know that, both the salts are acidic salts)
• NaH2PO4 -
Molar mass = 120 g/mol
Replaceable H+ ions = 2

Therefore, Equivalent mass =  $\frac{120}{2}$
= 60 g eq-1
• Na2HPO4 -
Molar mass = 142 g/mol
Replaceable H+ ions = 1

Therefore, Equivalent mass =  $\frac{142}{1}$
= 142 g eq-1