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Solve this: mau of O, in 2 rml O, • 3 4 01 I rml O, • 6 I I rrOl O. • 6 M gof O, • 6/EgofO, Eq. Of O] • 8 or simply by 3 07 • 2 Oz 96 g 02 96 g OJ 3. @uivaleM mass of-covalent follows. For example I mol glucoz n eqaivakr N_ - • 12 q H--un 12 2. Equivalent mass of an element in a redox For a redox change, equivalent truss of a substance is given by, Equivalent mass of an oxidant or reductant

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Please find below the explanation of the topic:

Equivalent mass of a substance (oxidant or reductant) is equal to molecular weight divided by number of electrons lost or gained by one molecule of the substance in a redox reaction.

Eq. wt. of O. A. =


Eq. wt. of R. A. =


Hope this information clears your doubts about the topic.

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