ST//RQ,PS=3cm and SR=4cm.find the ratio of triangle PST TO THE AREA OF TRIANGLE PRQ Share with your friends Share 0 Varun Rawat answered this Since, ST∥RQ and PR is a transversal, then∠PST = ∠PRQ Corresponding anglesSince, ST∥RQ and PQ is a transversal, then∠PTS = ∠PQR Corresponding anglesIn ∆PST and ∆PRQ∠PST = ∠PRQ Proved above∠PTS = ∠PQR Proved above⇒∆PST ~ ∆PRQ AA similarityWe know that ratio of area of 2 similar ∆'s is equal to the square of the ratio of their corresponding sides.Now, ar∆PSTar∆PRQ = PSPR2 = 372 = 949 5 View Full Answer