sum of 3 prime numbers is 100 if one of them exceeds another by 36 then one of the number is

Answer is 2, 31 and 67.
2+31+67 = 100.
Method
Sum of three prime number is 100 ie even number so one number must be 2
so 100- 2 = 98
now one prime number is 36 more than other
so a = b + 36
a + b = 98
b + 36 + b = 98
2b = 62
b = 31
and a= b+36 = 31+36 = 67 
a = 67
So three numbers are 2, 31 and 67.