The angle made by the line x+√3y-6=0 with positive direction of x axis is

note- 3 and y both are under root

Dear student,

Kindly find the answer to your query:
$$\begin{gathered} 3 \mathrm{and} \mathrm{y} \mathrm{both} \mathrm{cannot} \mathrm{be} \mathrm{within} \mathrm{root} \mathrm{only} 3 \mathrm{will} \mathrm{be} \mathrm{within} \mathrm{the} \mathrm{root}. \\ \mathrm{x}+\sqrt{3}\mathrm{y} -6 =0 \\ \mathrm{y} = -\frac{1}{\sqrt{3}}\mathrm{x}+\frac{6}{\sqrt{3}} \\ \mathrm{comparing} \mathrm{it} \mathrm{with} \mathrm{y} = \mathrm{mx}+\mathrm{c} \\ \mathrm{m} = \mathrm{tan\theta }= -\frac{1}{\sqrt{3}}= \tan 150 \\ \mathrm{So} \mathrm{angle} \mathrm{is} 150 \mathrm{degree} \end{gathered}$$

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