The angles of a quadrilateral are in a.p. whose common difference is 10degree.Find the angles.

let one of the angles be a

so other angles will be.....

a+10, a+20,a+30 (as the common difference is 10 degree)

a + (a+10) + (a+20) + (a+30) = 360 (angle sum property of a quadrilaterral)

4a + 60 = 360

4a = 300

a = 75..................a + 10 = 75 + 10= 85

similarly substitute value of a for all the 4 angles

answer will be....... 75,85,95,105 degrees