the area of rectrangular field is given by the expression (y2-11y+30)sq.m. find the dimensions of rectangle?

Please find below the solution to the asked query:

We have area of rectangle  = ( y² - 11 y  + 30 ) m²  , So we use splitting the middle term method and get

= y² - 6 y  - 5 y + 30

= y ( y  - 6 ) - 5 ( y  - 6 )

= ( y  - 5 ) ( y  - 6 )

Therefore,

Dimensions of rectangle  = ( y  - 5 ) m  and ( y  - 6 ) m                                                        ( Ans )


Hope this information will clear your doubts about topic.