the arithmetic mean of the series a+a+d+a+2d......(a+2nd) 
{ans is a+nd)



Dear Student,


The given Series is a, a+d, a+2d, a+3d, ..., a+2ndSo, its first term=aand common difference=dand mth term=a+2ndlet no. of terms be mSo, am=a+(m-1)da+2nd=a+(m-1)d2nd=(m-1)d2n=(m-1)m=2n+1So, nowSm=m2(a+am)Sm=2n+12(a+a+2nd)Sm=2n+12(2a+2nd)Sm=2n+122(a+nd)Sm=(2n+1)(a+nd)So, Arithmetic Mean=Smm=(2n+1)(a+nd)(2n+1)=a+ndHence Arithmetic Mean of the Series is a+nd.
Regards
 

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