The atomic diameter of an BCC crystal (if a is lattice parameter) is
  • 1.  a/2
  • 2.  a
  • 3.  a/(4/√3)
  • 4.  a/(4/√2)

Dear student
Please find the solution to the asked query:

It is observed from the figure that the atom at the centre is in contact with the other two atoms diagonally arranged.FromFED we haveb2=a2+a2b2=2a2b=2aAgain fromAFD we havec2=a2+b2c2=a2+ 2a2     [since b2 =2a2]c2=3a2c=3aif the radius of the atom is rlength of body diagonal c=4rthus   3a =4r             a =4r3            or r=3a4
Hence option 3 is correct.

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