# The base of an isosceles triangle is 4/3 cm. The perimeter of triangle is 4 2/15cm. what is the length of either of the remaining equal sides?

• 0

PERIMETER OF THE TRIANGLE= SUM OF THREE SIDES OF A TRIANGLE

ONE SIDE = 4/3CM  (GIVEN)

PERIMETER = 42/15CM(GIVEN)

HENCE PERIMETER - ONE SIDE OF THE TRIANGLE =LENGTH OF THE TWO SIDES OF THE TRIANGLE.

OR, 42/15 - 4/3 = 22/15

THEREFORE, LENGTH OF EACH OF THE REMAINING TWO SIDES = (22/15)/2 = 11/15

• -4

Is it 42/15 or 4(2/15) i.e.62/15

• 4

Ok

Let The Other Side Be x cm Each.

Now Perimeter = 4 2/15 = 62/15 cm

Now Perimeter Of A Triangle = Sum Of All The Sides

=> 2x+4/3 = 62/15

=> 2x = 62/15-4/3

=> 2x = 42/15

=> x = 42/15*1/2 = 21/15 cm = 7/5 cm

• 4

let the equal sides be x

perimeter=4 2/15=62/15 cm

acoording to the question,

x+x+4/3=62/15

i.e. 2x+4/3=62/15

2x=62/15-4/3

(lcm of 15 and 3=15 :. the fraction without the denominator as 15 will be changed)

i.e. 4/3=20/15

2x=62/15-20/15

2x=42/15

x=42/15*reciprocal of 2

x=42/15*1/2

x=14/5*1/2

x=7/5

• -4
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