the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class

Class mark of the distribution are 6, 10, 14, 18, 22, 26, 30

(a) Class size = difference between any two consecutive class marks = 10 - 6 = 4

Now first we have to find the classes for answering the forwarded question.

We know that if a is the class mark and h is its class size then lower limit and upper limit are 

 respectively.

Lower limit of the first class interval = = 6 - 2 = 4

Upper limit of the first class interval =

Similarly we obtain the other class limits as given under.

4 - 8

8 - 12

12 - 16

16 - 20 

20 - 24

24 - 28

28 - 32

(b) Lower limit of the second class = 8

(c) Upper limit of the last class = 32

(d) Third class = 12 - 16

  • 27

 Classes are 6-10, 10-14,14-18, 18-22, 22-26, 26-30

a) upper limit - lower limit = 4

b) 10

c) 30

d) 14-18

  • -3
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