# the concentration of NO3 ions when equal volumes of 0.1 M AgNO3 and 0.1 M Nacl are mixed together is ?

0.1M AgNO3 contains 0.1 moles of Ag+ and 0.1 moles of NO3- ions in 1L of solution. It was mixed with 0.1M NaCl of equal volume.

Here the quantity of NO3- is same but the volume is doubled. So its concentration will be reduced to half. So the concentration of NO3- is 0.05M

• 183
Here's it • -68
Here what u need***☜☆☞ • -65
0.05 Mole is the answer. As , AgNo3 + NaCl ----------> AgCl + NaNo3 At t=0 0.1 0.1 0 0 Let volume of each be 1L. So For Agno3 given mole is 0.1 and conc. Of no3 is also 1. So conc. Of No3- = 0.1/2 = 0.05 Here 0.1 is mol of Agno3 contributing towards ionisation and 2 is the total volume of solution in which this reaction took place
• 14
Here is the ans:- • 33
Simple 😇 • -29
As the relation between conc and volume is inversly proportional , the conc remained constant the vol is reduced to half • 4
• -12
0.1?2=0.05
As the solution contains 2 litre.
• -6 • -12 • -5
Pi =n1i1+n2i2. Pi=cRT then 0.1*3+0.1*2=0.05
• -1
Mokhtth
• -1 • 1
• -2
0.2 and 0.8
• -1
Hope this helps you • 3
?????? ?? ????????
• -1
Vapour pressure of pure water at 23?k is 19.8torr calculate the vapour pressure of 3m aqueous solution
• -1
nidan number Arakkonam explain and Angela • 0
Army
• 0
Maha
• 0
O.04 mole
• 0
• 0  