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The correct order of acidic character is

(1) P_{4}O_{10} > P_{4}O_{6}

(2) N_{2}O_{5} > N_{2}O_{3}

(3) N_{2}O_{3} > P_{4}O_{6}

(4) All of these

Answer is (4). Could you please explain why? And please explain each order? Thanks.

Acidic character of an oxide of element decreases with the decrease in oxidation state.

(1) Oxidation state of P in P

_{4}O

_{10}= +5

Oxidation state of P in P

_{4}O

_{6}= +3

Since P in P

_{4}O

_{10 }has higher oxidation state, therefore has more acidity.

(2)Oxidation state of N in N

_{2}O

_{5}= +5

Oxidation state of N in N

_{2}O

_{3}= +3

Since N in N

_{2}O

_{5}has higher oxidation state, therefore has more acidity.

(3)Now, as we go down the group, acidity of an oxide decreases. This is because on going down a group, atomic size increases, electronegativity decreases and hence metallic character increases. Therefore, N

_{2}O

_{3}is more acidic than P

_{4}O

_{6}.

Hence, the correct answer is (4)

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