the diameter of a circle is 10cm. the radius of this circle is taken as a diameter and another circle is drawn. a third circle is drawn with the radius of the second circle as its diameter. this process is repeated 'n' times until the diameter of the nth circle is less than 0.01cm. what is the least value of n?
Dear Student,
Please find below the solution to the asked query :
Dia of 1st circle = 10
Dia of 2nd circle = 10/2
Dia of 3rd circle = 10/4
Dia of 4th circle = 10/8
Dia of nth circle = 10/2^(n-1)
=> 10/2^(n-1) => 2^(n-1) > 1000
=> n-1 > 10
=> n > 11
=> n = 11
Hope this would clear your doubt about the topic.
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Please find below the solution to the asked query :
Dia of 1st circle = 10
Dia of 2nd circle = 10/2
Dia of 3rd circle = 10/4
Dia of 4th circle = 10/8
Dia of nth circle = 10/2^(n-1)
=> 10/2^(n-1) => 2^(n-1) > 1000
=> n-1 > 10
=> n > 11
=> n = 11
Hope this would clear your doubt about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards