The diode used in the circuit shown in the figure has a constant voltage drop of 0.5V at all currents and a maximum power rating 100mW. What should be the value of the resistor R connected in series with the diode for obtaining maximum current
A) 1.5 ohm
B) 5 ohm
C) 6.67 ohm
D) 200 ohm
Given:
- Diode's Voltage Drop, Vd = 0.5V
- Maximum Power Rating, P = 100mW = 0.1 Watts
- Battery EMF, E = 1.5V
- Resistance = R
1) Finding Current in the Circuit:
So it's given E = 1.5V and Vd = 0.5V
Formula: P = I*Vd => I = (P/Vd)
I = (0.1/0.5)
= 0.2A
2) Finding Potential Drop Across R
V = E – Vd
= 1.5 - 0.5
= 1V
3) Finding Value of R
From above, V = 1V and I = 0.2 A
V = IR
R = V / I
= 1 / 0.2
= 5 ohms
Hence the answer is B. :)
- Diode's Voltage Drop, Vd = 0.5V
- Maximum Power Rating, P = 100mW = 0.1 Watts
- Battery EMF, E = 1.5V
- Resistance = R
1) Finding Current in the Circuit:
So it's given E = 1.5V and Vd = 0.5V
Formula: P = I*Vd => I = (P/Vd)
I = (0.1/0.5)
= 0.2A
2) Finding Potential Drop Across R
V = E – Vd
= 1.5 - 0.5
= 1V
3) Finding Value of R
From above, V = 1V and I = 0.2 A
V = IR
R = V / I
= 1 / 0.2
= 5 ohms
Hence the answer is B. :)