The displacement "x" of a particle in metres along the y-axis and time 't' in seconds along the x-axis, according to the equation- X=20m +(12m/s)t
(a) Draw a graph if x versus t for t=0 and t=5 sec
(b) What is the displacement come out of the particles initially?
(c) What is slope of the graph obtained?

x = 20+12tat t = 0x = 20at t = 5sx = 80 mslope of the graph =v = dxdt = 0+12= 12 m/sacceleration = 0hence this is unniform velocity motion, so graph between distance and time will be linear.

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