The distance x of a particle moving in 1 dimension under the action of a constant force is related to time t by equation t = root over x + 3 where x is in metres and t is in seconds . Find the displacement when it's velocity is zero.
I don't undrstand the root is over x + 3 or just x, so i will solve both cases.
t = √x + 3
on squaring
√x = t - 3
x = t2 - 6t + 9
Now differentiate x wrt t, dx/dt is velocity
dx/dt = 2t - 6
velocity v = 2t - 6
v = 0
2t - 6 = 0
that gives t = 3
at t = 3 ,
x = 3 - 3
0 displacement