The energy difference between two electronic states of hydrogen atom is 245 9 kJ mol-1 Calculate the wavelength of - Chemistry - Structure of Atom

Question

The energy difference between two electronic states of hydrogen
atom is 245 9 kJ mol-1 Calculate the wavelength of light
emitted when an electron drops from the higher to the lower state
(plank's constant, h=3 99 10-13 kJ Sec mol-1)

Geetha · Accepted Answer

∆E= hν   = hCλ249
5 × 103   = 3
99 × 10-13 × 103 × 3 × 108λ    (h =3
99 ×10-13 kJ sec mol-1= 3
99 ×10-13 × 103 J sec mol-1)λ =3
99 × 10-13 × 103 × 3 × 108249
5 × 103  = 0
04798 × 10-5 m     = 479
8 × 10-9 m     = 479
8 nm

The energy difference between two electronic states of hydrogen atom is 245.9 kJ mol-1. Calculate the wavelength of light emitted when an electron drops from the higher to the lower state. (plank's constant, h=3.99. 10-13 kJ.Sec.mol-1)

The energy difference between two electronic states of hydrogen atom is 245.9 kJ mol^-1. Calculate the wavelength of light emitted when an electron drops from the higher to the lower state. (plank's constant, h=3.99. 10^-13 kJ.Sec.mol^-1)