The HCF and LCM of two numbers are 4 and 288 respectively. Find the numbers and how many such pairs are possible.
 

Dear Student,

We know that, Product of two numbers = H.C.F×L.C.M
Suppose other two numbers are A and B.so we can write;
A×B = 4×288A = 4×288B
Taking  B = 32; then A = 4×28832 = 36
Therefore other number is 36 if one number is 32.

So, (32 36) is one of the pair that satisfies the above conditions.

Regards.

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