the height at which the weight of a body becomes 1/ 16 its weight on the surface of earth is Share with your friends Share 6 Vara answered this Expression for weight:W α gW2W1=g2g1 =r1r22 =RR+h2W2W1=RR+h2116=RR+h214=RR+hR+h=4Rh=3RSubstitute radius of earth, R=6400 kmh=3×6400 km =19200 km 45 View Full Answer Gayathri answered this mg= W W'= W/16 if weight should become 1/16, g should become 1/16, since mass cannot change. g' = (g)/( 1+ h/R)2 = 10/(1+h/6400)2 g' = 10/16 i.e, 10/16= 10/ (1 + h/ 6400)2 (1 + h/6400 )2 = 16 1+ h/6400 = + or - 4 h/6400= 3 h = 6400 x 3 = 19200km. 17 Gayathri answered this Please write this down in paper. W = mg = m x (GM/R2) Wh = m x (GM/(R+ h)2) Wh/W = R2/ (R+ h)2. = 1/16 (Others get cancelled) R/ R+h = 1/4 4R= R+ h h= 3R= 6400x 3 = 19200km 18
