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the height of a tower is 200m. when the altitude of the sun is 300 , find the length of its shadow.



Let AB be the tower.Let ∠ACB = 30°Let BC be the shadow of tower.Now, tan 30° = ABBC⇒13 = 200BC⇒BC = 2003 m

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h = 200m(opposite side)
​theta = 30o
∴tan30o=​ opposite side / adjacent side.
Complete it from here!!! :D
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o = AB/BC
1/√3 = 200/BC
BC = 200√3 m
Thus, length of shadow , BC = 200√3 m.

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height of the tower = 200m
length of its shadow = ?
In triangle ABC, we have
tan 30o = AB/BC
1/√3 = 200/BC
BC = 200√3 m
Thus, length of shadow , BC = 200√3 m.

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