The height of a tree, if it casts a shadow 17m long on the level of ground, when the angle of elevation of the sun is 45 degree is:
a) 17 m
b) 8 m
c) 10 m
​d) 14m



Let AB be a tree and BC be its shadow.Let ACB = 45°Now, BC = 17 mtan 45° =  ABBC1 = AB17AB = 17so, height of the tree = 17 m

  • 5
a) 17 m.

This is because :-

It forms A Triangle , ABC ,

In ABC :-

Tan 45 = O / A

1 = 17 / A

A = 17 m.
  • 3
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