The height of right circular cone is trisected by two plane parallel to its base. Show that the volume of the three propotion from top are in ratio 1:7:19.

Let VAB be a right circular cone of height 3*h* and base radius *r*. Thus cone is cut by planes parallel to base at point of and L such that VL = L O´ = *h*.

Since ∆VOA and ∆VB´A´ are similar

Also ∆VOA ~ ∆VLC

Let V_{1} be the volume of cone VCD then

Let V_{2} be the volume of the frustum A´B´DC. Then

Let V_{3} be the volume of the frustum ABB´A´. Then

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