The initial velocity of a particle is u (at t= 0) and the acceleration a is given by alpha t3/2. Which of the following relations is valid?
1. v = u + αt3/2
2. v = u + 3/2αt3
3. v = u +2/5αt5/2
4. v = u + αt5/2

  • 4
But the answer given is 3rd..
  • 17
velocity = acceleration * t final velocity = u + a t^{3/2) t = u + a t^(3/2 + 1) b = u + a t^(5/2)b To caluclate b, use the acceleration by d final velocity/dt = 5/2 a b t^(3/2) Compare this with acceleration You will get b = 2/5 The answer will be velocity final = u + a 2/5 t^(5/2)
  • -21
Why we have to integrate alpha t3/2. Please give reason, it is confusing that why option 4 is not correct
  • 16
here is the ans friends ok by
  • -17
That will do 😊

  • 110
Here is the answer

  • 62
As a=dv/dt

  • 12
answer

  • 5
Leave ans aside...the most imp. Step is here the acceln is variable... u cant use 3 equations of motion..
  • 1
We have to assume as a = dv/ dt and later c is equal to u

  • 0
Answer is (3) option Hope it helps u !!
  • -1
as acceleration is dependent on time it is non uniform accelerated motion so we cannot use kinematic equation.
so we should use calculus, now integrate the acceleration to find velocity with proper limits and you'll get 3rd option as your answer which is correct
  • 3
What are you looking for?