​​The length of room is y metres. Write the breadth of the room which is 20 metres less than twice the length. Write an expression for the perimeter of the room.

Given, length of room=y metersAccording to question,Breadth of room=2y-20Now,Perimeter of room=2Length+Breadth=2y+2y-20=23y-20=6y-40Perimeter of room=6y-40

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PERIMETER OF RECTANGLE = 2( LENGTH+ BREADTH )
HENCE, PERIMETER OF RECTANGULAR ROOM= 2[ Y + (2Y - 20 ) ]

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Let length be y metres & breadth be 2y - 20.
Therefore,Perimeter of the room ={ 2 [ y + ( 2y - 20 ) ] }
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