the magnetic moment of auto catalyst formed in the reaction between acidified oxalic and pottasium permanganete ?

Dear Student,

The reaction of acidified oxalic acid and potassium permanganate is:
2MnO₄^- + 5H₂C₂O₄ + 6H⁺ ----> 2Mn²⁺ + 10CO₂ + 8H₂O
The autocatalyst in the reaction are the ions formed in the reaction. In this reaction, the ion formed is Mn2+.
The magnetic moment of Mn²⁺ is:
Magnetic moment = $\sqrt{n(n+2)}$
n = number of unpaired electrons
The electronic configuration of Mn²⁺ is [Ar]3d⁵.
Number of unpaired electrons = 5
So, magnetic moment is: $\sqrt{n(n+2)} = \sqrt{5(5+2)}= \sqrt{35}$ = 5.92
Magnetic moment of auto catalyst is 5.92.

Regards