The.maximum tension in the string of a pendulum is three times the minimum tension.If Ɵ0 be the angular amplitude, then why is,cos Ɵ0 3/5

Using Conservation of Energy,mgh=12mv2As length of string is lh=l-lcosθv2=u2+2gh:   u=0v2=2ghputting value of hv2=2gl(1-cosθ)Maximum tension  =mg+mv2lminimum tension  =mgcosθAccording to questionmg+mv2l=3mgcosθputting value of vmg+2mg(1-cosθ)=3mgcosθ3-2cosθ=3cosθcosθ=3/5

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