The maximum value of log𝑥 / 𝑥 is at a) 𝑥= e b) 𝑥 = 1/𝑒 c) 𝑥= 1 d) 𝑥= 2/e Share with your friends Share 0 Atul Shaw answered this Dear student,let f=log xxdfdx=log x-x×1xx2=0log x-1=0log x=1x=eOption A is correct.Regards 0 View Full Answer
