The number of real values of λ for which the system of linear equations 2x+4y λz=0 4x+λy+2z=0 λx+2y+2z=0 has infinitely - Maths - Linear Inequalities

Question

The number of real values of λ for which the system of
linear equations 2x+4y−λz=0 4x+λy+2z=0
λx+2y+2z=0 has infinitely many solutions, is :​

Brijendra Pal · Accepted Answer

Hi, Determinant formed by these equation has value zero then solutionsare infinite 24-λ4λ2λ22=022λ-4-48-2λ-λ8-λ2= 0 4λ-8-32+8λ-8λ+λ3= 0 λ3+4λ-40= 0 but its roots are in fraction and imaginary and that is above your grade

The number of real values of λ for which the system of linear equations 2x+4y−λz=0 4x+λy+2z=0 λx+2y+2z=0 has infinitely many solutions, is :​

The number of real values of λ for which the system of linear equations 2x+4y−λz=0 4x+λy+2z=0 λx+2y+2z=0 has infinitely many solutions, is :