the parking charges of a car on New Delhi railway station for first 2 hours is Rs 50/- and Rs 10/-for subsequent hours.write down a equation & draw the graph of this data.Read the charges from the graph.

1)for 1 hour  2)for 3 hours 3) for 6 hours

Let total hours =  x

total charges = y

charges for 2 hours= Rs. 50

charges for more than 2 hours = Rs. 10

Now remaining hours= x-2

total charges for remaining hours = Rs 10(x-2)

Total charges= charge for first two hours + charge for remaining hours

 y = 50 + 10 (x-2)

hence the equation is  y = 30 + 10x

Now draw the graph as below

from the graph it is clear that 

when x = 1 y= 40 , 

when x= 3 y= 60 and 

when x= 6 y= 90

u can put different values of x in the equation to obtain different values of y.

  • 53

Let total distance be x km & total fare = Rs y 

y = 50 + (x - 2) * 10

= 50 + 10x - 20 

= 30 + 10x

Thumbzz up plz ??

  • -11
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