The partial pressure of ethane over a solution containing 6.56 × 10−3 g of ethane is 1 bar. If the solution contains 5.00 × 10−2 g of ethane, then what shall be the partial pressure of the gas?

Molar mass of ethane (C2H6) = 2 × 12 + 6 × 1

= 30 g mol−1

Number of moles present in 6.56 × 10−2 g of ethane

= 2.187 × 10−4 mol

Let the number of moles of the solvent be x.

According to Henry’s law,

p = KHx

Number of moles present in 5.00 × 10−2 g of ethane

= 1.67 × 10−3 mol

According to Henry’s law,

p = KHx

= 7.636 bar

Hence, partial pressure of the gas shall be 7.636 bar.

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