The perimeter of a sector of circle with central angle 90 is 25 cm. Find the area of minor segment

Let r be the radius of a sector of a circle with center at O.

Length of the arc ACB = l = θ360°×2πr= 90360×2×227×r = 11r7cm

perimeter of the sector AOBCA = 25 cm

r + r + l = 25 ⇒ 2r + 11r7= 25  ⇒ r = 7 cm

area of the minor segment ABCA = Area of the sector AOBCA - area of Δ AOB



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