The perimeter of a triangle is 7x^2-17xy+5y^2+8 and two of its sides are 4x^2-7xy+4y^2-3 and 5+6y^2-8xy+x^2 Find the third - Maths - Algebraic Expressions and Identities

Question

The perimeter of a triangle is 7x^2-17xy+5y^2+8 and two of its
sides are 4x^2-7xy+4y^2-3 and 5+6y^2-8xy+x^2 Find the third side of
the triangle

Ankita Agarwal · Accepted Answer

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The perimeter of a triangle is 7x^2-17xy+5y^2+8 and two of its sides are 4x^2-7xy+4y^2-3 and 5+6y^2-8xy+x^2. Find the third side of the triangle.