# The population of a town increases from 1,60,000 to 1,80,000 in a year. Find the percentage increase in the population of the town.

$Initialpopulation=1,60,000;Increasedpopulation=1,80,000\phantom{\rule{0ex}{0ex}}\therefore Changeinpopulation=1,80,000-1,60,000=20,000\phantom{\rule{0ex}{0ex}}Thus,percentageincrease=\frac{Changeinpopulation}{Initialpopulation}\times 100=\frac{2\overline{)0,000}}{1,6\overline{)0,000}}\times 100=\frac{100}{8}=12.5\%$

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