The potential energy of a particle of mass 5 Kg moving in x-y plane is given as U = (7x - Physics - Work Energy And Power

Question

The potential energy of a particle of mass 5 Kg moving in x-y plane
is given as U = (7x + 24y ) j , x and y being in metre Initially at
t=0 , the particle is at the origin ( 0, 0 ) moving with a velocity
of ( 8 6i + 23 2j ) ms-1 Then

the velocity of the particle at t = 4s , is 5
ms-1
the acceleration of the particle is 5 ms-2
the direction of motion of the particle initially is at right
angles to the direction of acceleration
the path of the particle is circle

Vaibhav T. · Accepted Answer

Dear Student,

potential energy, U=7x+24y Jmass, m=5 kgFx=-dUdxFx=-7xFy=-dUdyFy=-24F=Fx2+Fy2F=-72+-242F=49+576F=625=25 Nacceleration, a=Fma=255=5 m/s2