The reaction 2N2O5 → 4NO2 + O2 takes place in closed container. If the concentration of NO2 increases by 1.6 x 10-2 mol/lt in 4 sec,calculate the rate of the reaction and the rate of change of concentration of N2O5.
Reaction is
2N2O5 4NO2 + O2
Rate =
Rate =
Rate = 1.0 10-3 mol L-1 s-1
Thus, the rate of reaction is 1.0 10-3 mol L-1 s-1.
Now, rate of change of concentration of N2O5
Rate =
1.0 10-3 mol L-1 s-1 =
= 2 1.0 10-3 mol L-1 s-1
= 2.0 10-3 mol L-1 s-1
2N2O5 4NO2 + O2
Rate =
Rate =
Rate = 1.0 10-3 mol L-1 s-1
Thus, the rate of reaction is 1.0 10-3 mol L-1 s-1.
Now, rate of change of concentration of N2O5
Rate =
1.0 10-3 mol L-1 s-1 =
= 2 1.0 10-3 mol L-1 s-1
= 2.0 10-3 mol L-1 s-1