the resistance of a silver wire at 0 degree celsius is 1.25 ohm.upto wat temp. it must b heated so dat its resistance is doubled?(alpha silver=0.00375/degree celsius.will d temp. be same for all silver conductors of all shapes??
we know that
RT = R0 [1 + α (T − T0)]
which can be rearranged as
T = T0 + (1/α)[1 - (RT/R0)]
here we have assumed that the shape and configuration of the conducting wire remains constant.
now, we are given
R0 = 1.25 ohms
RT = 2R0 = 2.5 ohms
α = 0.00375 /C
T0 = 0 C
TT =
thus,
T = 0 + (1/0.00375)[1 - (2.5/1.25)]
or
T = 266 C