The root of the quadratic equation x^2+5x-(alpha+1)(alpha+6)=0 where alpha is the constant are,

1. ​alpha+1, alpha+6
​2. alpha+1, -(alpha+6)
​3. -(alpha+1), alpha+6
​4. -(alpha+1), -(alpha+6)

The given quadratic equation is,    x2 + 5x - α+1α+6 = 0x2 + α+6x - α+1x - α+1α+6 = 0xx + α+6 -  α+1x + α+6 = 0x - α+1x + α+6 = 0x - α+1 = 0  or   x + α+6 = 0x = α+1   or   x = - α+6

  • 6
Option 2 is correct
  • 0
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