the sides of a triangle are 16 cm , 30 cm and 34 cm. its area ?

Suppose the sides of triangle are a, b and c
Where a = 16 cm; b = 30 cm and c = 34 cm
And S the semi perimeter of triangle.
So, S = a+b+c2 = 16+30+342 = 802 = 40
According to the heron's formula we have;
Area; A = SS-aS-bS-c
= 4040-1640-3040-34=40×24×10×6=57600=240
So, the area of triangle is 240 square centimeter

  • 5

Let a,b and c be 16, 30 and 34 cm respectively

Semiperimeter(S) = a+b+c/2

= 16+30+34/2

= 40

Area of triangle = √s(s-a)(s-b)(s-c)

=√40*(40-16)(40-30)(40-34)

=√40*24*10*6

=√57600

=24 cm2

  • 0

Let the semi-perimeter be x and the triangle be ABC, where AB = 16 cm, BC = 30cm and AC = 34 cm.

Perimeter = 16 + 30 + 34 = 80 cm.

Semi-perimeter(x) = 80/2 = 40 cm.

Heron's Formula = root of x(x-ab)(x-bc)(x-ca)

=root of 40(40-16)(40-30)(40-34)

=root of 40(24)(10)(6)

=root of 57600 cm4

=240 cm2

  • 4

unfortunately, this is not the correct answer . the correct answer is 225 under 3 sq cm.

  • 2
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