The sides of a triangle are 5 cm,12 cm and 13cm.find the length of perpendicular from the opposite vertex to the side whose length is 13cm

plzs frndzzz fast reply becoz monday is my exam so plzs telll dis ques.

• -5

Area Of Triangle = Square Root Of (S(S-A)(S-B)(S-C))

Now S = 5+12+13/2 = 15

Now Simply

Area = Square Root Of (15*10*3*2)

Area = Square Root Of (900)

Area = 30

Now Area Of Triangle = 1/2*Base*Height

Now Base = 13

Now

1/2*13*Height = 30

13*Height = 60

Height = 60/13 = 4.61 cm

• 64
find area using herons formula first, then use 1/2 bh to find h.
if you get the answer, pls like it
• 13
VERY GOOD PRAKHAR

• -4
ITS VERY SIMPLE JUST PUT HERONS FORMULA AND THEN USE 1/2* BASE *HEIGHT TO FIND H AND PLEASE LIKE
• 2
i will kidnap you
• -6
a=root of s[s-a][s-b]
• -2
Equal chords of circle are equal distance from the centre prove it
• -1
Let's say that the triangle is ABC with AB = 12, BC = 5, CA = 13. Now you may see that triangle is right-angled at B, as AB² + BC² = CA². And AB ⟂ BC with CA as hypotenuse and perpendicular's foot on CA be D. Hence, ar(ABC) = ½ AB · BC = ½ CA · BD. ⇒ BD = ( AB · BC ) ÷ CA = ( 12 × 5 ) ÷ 13 = 60/13 cm
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