The sides of a triangular park are in ratio 6:7:8 and perimeter is 420m. Find it's area and te length of the perpendicular drawn on the biggest side.

Let the sides of the triangle are :

a = 6x  , b = 7x , c = 8x

now, a + b + c = 420

so, 6x + 7x + 8x = 420 ⇒ x = 20

so, a = 120 cm , b = 140 cm , c = 160 cm

semi perimeter = s = 210 cm

perpendicular  =  (2 × area) / longest side = 4200√15 / 160

 =

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Let the common ratio of the sides be x.

Then the sides are 6x,7x and 8x.

6x + 7x + 8x = 420

21x = 420

x = 20

Therefore the three sides are 6x = 120 = a , 7x = 140 = b and 8x = 160 = c.

Semi-Perimeter of the triangle (s) = 420/2= 210

Therefore Area of Triangle = Square Root of s*(s-a)*(s-b)*(s-c) [Heron's Formula]

= Square root of ( 210 * (210 - 120)*(210 - 140)*( 210-160)

=Square Root of ( 210*90*70*50)

=Square Root of 66150000

= 8133.265m (Approx) = Area of the triangle.

I'm working on the other part, but till then, hope this helps :)

  • 0

Let the common ratio of the sides be x.

Then the sides are 6x,7x and 8x.

6x + 7x + 8x = 420

21x = 420

x = 20

Therefore the three sides are 6x = 120 = a , 7x = 140 = b and 8x = 160 = c.

Semi-Perimeter of the triangle (s) = 420/2= 210

Therefore Area of Triangle = Square Root of s*(s-a)*(s-b)*(s-c) [Heron's Formula]

= Square root of ( 210 * (210 - 120)*(210 - 140)*( 210-160)

=Square Root of ( 210*90*70*50)

=Square Root of 66150000

= 8133.265m (Approx) = Area of the triangle.

And the length of the perpendicular to it's longest side = Square root of 8000

= 89.44271 Approx

(Lol, took half an hour to solve the full question :P)

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