The solution of the equation m/x + n/y =a , n/x + m/y = b is given by
1) x= n² + m² / am - bn , y= m² - n² / bm - an
2) x = m² - n² / am - bn , y = n² - m² / bm - an
3) x= m² - n² / am - bn , y = m² - n² / bm - an
4) x= n² - m² / am - bn , y = n²- m² / bm - an

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Please find below the solution to the asked query:

The given equations are:mx+ny=a          .....1nx+my=b         .....2Multiply equation1 by n and equation2 by m, we get,mnx+n2y=an          .....3nmx+m2y=bm         .....4Subtracting equation3 and 4, we get,1yn2-m2=an-bmy=n2-m2an-bmy=m2-n2bm-anSubstitute value of y in equation 1, we get,mx+nan-bmn2-m2=amx=a-nan-bmn2-m2mx=an2-am2-an2+bmnn2-m2x=m2-n2am-bnHence x=m2-n2am-bn and y=m2-n2bm-an
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  • 10
Given equations are : (1) m/x + n/y = a
(2) n/x + m/y = b
let 1/x = u & 1/y = v
then, m/x+n/y = mu+nv
And, n/x + m/y = nu+mv
so, new equations are : (1) mu+nv = a or, mu+nv - a = 0 (2) nu + mv = b or, nu+mv-b = 0
Solving for u and v by cross-multiplication method :
u = (b1c2-- b2c1) ÷ (a1b2 - a2b1)
=》u= [n×(-b) --m × (-a)]÷ (m×m - n×n )
=》u = (-bn+am)÷(m^2-n^2)
=》u= (am-bn)÷(m^2-n^2)
Now, u= 1/x
so, x = (m^2 - n^2)÷(am-bn)
similarly,
v = (c1a2 - c2a1 )÷(a1b2 - a2b1)
=》v= [(-a)×n - (-b)×m] ÷(m×m -n×n )
=》v=(bm- an)÷(m^2 -n^2)
Now, v= 1/y
so, y = (m^2 - n^2)÷(bm-an)

Hence, x= (m^2 - n^2)÷(am-bn) &
y = (m^2 - n^2)÷(bm-an)

so, correct option is (3).
  • 3
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