The specific conductance of a saturated solution of AgCl at 25°C after subtracting the specific conductance of conductivity of water is 2.28 × 10^–6 mho cm^–1. Find the solubility product of AgCl at 25°C.
$\left({\mathrm{\lambda }}_{\mathrm{AgCl}}^{\infty }=138.3 \mathrm{mho} {\mathrm{cm}}^2\right)$