The sum of four consequtive positive integers is "X". In terms of "X", what is the sum of the second and third integers?

a) x/2 b) x-12/4 c) x-6/2 d) 2x+6

Suppose the four consecutive positive integers are a, a + 1, a + 2, a + 3.
So the sum of four consecutive positive integers is X, so we have;
$$\begin{gathered} a+a+1+a+2+a+3 = X \\ \Rightarrow 2a+3+2a+3 = X \\ \Rightarrow 2\left(2a+3\right) = X \\ \Rightarrow \left(2a+3\right) = \frac{X}{2} \end{gathered}$$
And the sum of second and third consecutive integers = a + 1 + a + 2 = 2a + 3
Therefore, the sum of second and third consecutive integers = 2a + 3  = $\frac{X}{2}$.
So option (a) is correct.