The sum of n 2n 3n terms of an AP are S1 S2 S3 respectively. Prove that S3=3(S2-S1).

Dear Student!

Here is the answer to your question.

Let the first term of the A.P. be a and the common difference be d.

According the question,

We have to prove that  S3 = 3 ( S2 – S1).

R.H.S = 3 (S2 – S1)

 

 = S3

 = L.H.S

⇒ S3 = 3 ( S2 – S1)

Cheers !

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