the sum of n terms of a sequence is 3n^{2}+4n.find the nth term and show that sequence is an A.p

Given, sum of *n* terms of the A.P., .

Replacing *n* by (*n* – 1) in , we get

Thus, the *n*^{th} term of the A.P. is 6*n* + 1.

**A sequence is an A.P. if its ****n**^{th}** term is a linear expression in *** n. *The

*n*

^{th}term of the given sequence is a linear expression in

*n*, so the sequence is an A.P.

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