The summ of square of two consecutive natural number is 313. The number are
A. 12,13. B. 13,14. C. 11,12. D. 14,15
Dear student,
Let the number be x and x+1
x2+(x+1)2=313
x2+x2+2x+1=313
2x2+2x-312
x2+x-156=0
x2+13x-12x-156=0
x(x+13)-12(x+13)=0
(x+13)(x-12)=0
x= -13,12
x can't be negative as x is a natural number.
Thus, x=12
So, x+1=13
Option A is correct.
(a+b)2=a2+2ab+b2
Regards
Let the number be x and x+1
x2+(x+1)2=313
x2+x2+2x+1=313
2x2+2x-312
x2+x-156=0
x2+13x-12x-156=0
x(x+13)-12(x+13)=0
(x+13)(x-12)=0
x= -13,12
x can't be negative as x is a natural number.
Thus, x=12
So, x+1=13
Option A is correct.
(a+b)2=a2+2ab+b2
Regards