The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Total distance covered = x km

Fare for 1st kilometre = Rs 8

Fare for the rest of the distance = Rs (x − 1) 5

Total fare = Rs [8 + (x − 1) 5]

y = 8 + 5x − 5

y = 5x + 3

5xy + 3 = 0

It can be observed that point (0, 3) and satisfies the above equation. Therefore, these are the solutions of this equation.






The graph of this equation is constructed as follows.

Here, it can be seen that variable x and y are representing the distance covered and the fare paid for that distance respectively and these quantities may not be negative. Hence, only those values of x and y which are lying in the 1st quadrant will be considered.

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