the units digit of a two digit number is 3 and seven times the sum of the digits is the number itself. find the number.

**Given that –**

Unit digit of the number = 3

Let tens digit of the number = *x*

then, the number will be = 10 × *x* + 3

= 10 × *x* + 3 ... (1)

According to Question –

10*x* + 3 = 7 (3 + *x*)

⇒ 10*x* + 3 = 21 + 7*x*

⇒ 3*x* = 18

⇒ *x* = 6

Hence, the number is 10 × 6 + 3 = 63

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