the units digit of a two digit number is 3 and seven times the sum of the digits is the number itself. find the number.

Given that –

Unit digit of the number = 3

Let tens digit of the number = x

then, the number will be = 10 × x + 3

 = 10 × x + 3  ...  (1)

According to Question –

10x + 3 = 7 (3 + x)

⇒ 10x + 3 = 21 + 7x

⇒ 3x = 18

⇒ x = 6

Hence, the number is 10 × 6 + 3 = 63